Group an array on the basis of array keys in php -
i have array structure this,which coming loop:
$a = array('9-aug','$50','room1'); $b = array('10-aug','$60','room1'); $c = array('9-aug','$70','room2'); $d = array('10-aug','$80','room2'); i need data this(i.e) group data on basis of date:
['9-aug-2014']=>{ [0]=>{'$50','room1'}, [1]=>{'$70','room2'} } ['10-aug-2014']=>{ [0]=>{'$60','room1'}, [1]=>{'$80','room2'} } is there function ? have tried using array_map, can't desired o/p. here have tried:
$e = array_map(null, $a, $b, $c,$d); print_r($e); and got:
array ( [0] => array ( [0] => 9-aug [1] => 10-aug [2] => 9-aug [3] => 10-aug ) [1] => array ( [0] => $50 [1] => $60 [2] => $70 [3] => $80 ) [2] => array ( [0] => room1 [1] => room1 [2] => room2 [3] => room2 ) ) please help.i can't format $a,$b,$c,$d arrays, way data fetched.
how format data can visible in format.
<table class="price-breakdown"> <thead> <!--<tr><th></th><th style="font-weight:normal" colspan="3">price per room (inc vat & taxes)</th></tr>--> <tr> <th class="date-col">date</th> <th class="date-col">room</th> <th valign="top"> premier saver <br> <span class="pbthsubtitle"> price per room<br>(inc vat & taxes) </span> </th> </tr></thead> <tbody> <tr> <td> <nobr>wed 17 sep 14</nobr> </td> <td align="left">1</td> <td> £<span>71.00</span> </td> </tr> <tr> <td> </td> <td align="left">2</td> <td> £<span>71.00</span> </td> </tr> <tr> <td> </td> <td align="left">3</td> <td> £<span>71.00</span> </td> </tr> <tr> <td> <nobr>thu 18 sep 14</nobr> </td> <td align="left">1</td> <td> £<span>67.00</span> </td> </tr> <tr> <td> </td> <td align="left">2</td> <td> £<span>67.00</span> </td> </tr> <tr> <td> </td> <td align="left">3</td> <td> £<span>67.00</span> </td> </tr> <tr> <td> <nobr>fri 19 sep 14</nobr> </td> <td align="left">1</td> <td> £<span>83.00</span> </td> </tr> <tr> <td> </td> <td align="left">2</td> <td> £<span>83.00</span> </td> </tr> <tr> <td> </td> <td align="left">3</td> <td> £<span>83.00</span> </td> </tr> </tbody> <tfoot> <tr class="yellow-top"> <td colspan="5"></td> </tr> <tr> <td class="date-col"> <nobr>total 3 nights </nobr> </td> <td>3 rooms</td> <td> £<span>663.00</span> </td> <td> £<span>744.00</span> </td> <td> £<span>822.75</span> </td> </tr><tr class="yellow-btm"><td colspan="5"></td></tr></tfoot> </table>
this can done following code. , working script available @ following url: http://sugunan.net/demo/array4.php
$a = array('9-aug','$50','room1'); $b = array('10-aug','$60','room1'); $c = array('9-aug','$70','room2'); $d = array('10-aug','$80','room2'); $arr = array($a,$b,$c,$d); $arr_merge = array(); foreach($arr $key_dim1=>$val_dim1) { $arr_merge[$val_dim1[0]][] = array($val_dim1[1],$val_dim1[2]); } print_r($arr_merge); the table creation part array
<table class="price-breakdown"> <thead> <tr> <th class="date-col">date</th> <th class="date-col">room</th> <th valign="top">premier saver<br> <span class="pbthsubtitle">price per room<br>(inc vat & taxes)</span> </th> </tr> </thead> <tbody> <?php foreach($arr_merge $key1=>$val1){ foreach($val1 $key2=>$val2){ ?> <tr> <td><nobr><?php if($key2==0){ echo $key1; } ?></nobr></td> <td align="left"><?php echo $val2[1]; ?></td> <td><?php echo $val2[0]; ?></td> </tr> <?php }} ?> </tbody> </table> 
Comments
Post a Comment