java - printing 2 times donno why -

i having problem when break out remove part code prints main menu options twice

there no error in code , runs why print twice instead of once?

 public void mainloop() {     (int = 0; < 100; i++) {          string x;          system.out.println("please select option");         system.out.println("............................");         system.out.println("1 add name , number \n2 remove name , number \n3 search name , number \n0 exit");         system.out.println("............................");          x = input.nextline();          if (x.equalsignorecase("0")) {             system.out.println("thank you!");             break;         }         if (x.equalsignorecase("1")) {             string name;             string number;              system.out.println("please enter name below");             name = input.nextline();             system.out.println("please enter number below");             number = input.nextline();             system.out.println("");             system.out.println("your name " + name + " , number " + number + " has been saved!\n");              objectclass objectclassobject = new objectclass(name, number);             test.add(objectclassobject);         }         if (x.equalsignorecase("2")) {              system.out.println("-------all name , numbers-------");             system.out.println("");              (int j = 0; j < test.size();) {                 objectclass p = test.get(j++);                 system.out.println(j + ". name: " + p.getname() + " - " + p.getnumber());             }             (int j = 0; j < test.size(); j++) {                 system.out.println("");                 system.out.println("enter index number remove contact phonebook!");                 int v = input.nextint();                 int temp = (v - 1);                 if (v >= 1 && v <= test.size()) {                     system.out.println("name: " + test.get(temp).getname() + " , number: " + test.get(temp).getnumber() + " has been removed!!");                     system.out.println("");                     test.remove(temp);                 } else {                     system.out.println("please enter number properly!!");                 }                 break;             }         }         if (x.equalsignorecase("3")) {             string y;             system.out.println("*** enter name below search ***");             y = input.nextline();              (objectclass p : test) {                 string z = p.getname();                 if (z.equalsignorecase(y)) {                     system.out.println("your name is: " + p.getname() + "\nyour number is: " + p.getnumber());                     system.out.println("");                 }                 if (!z.equalsignorecase(y)) {                     system.out.println("contact not found!!!");                 }             }         }     } } 

}

system.out.println("please select option"); system.out.println("............................"); system.out.println("1 add name , number \n2 remove name , number \n3 search name , number \n0 exit"); system.out.println("............................"); 

this prints twice :/~

if prints twice, went 2 times thru loop. try display variable 'x' after reading it. bet have empty strings between legitimate input.

what happens nextint() doesn't consume newline. therefore, next time read x read end of line after value v.