connection - Python's urllib2 won't connect... to anything -

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i can ping , can see google.com in browser same machine, when try use urllib2.urlopen(url) fails. why?

tmac:~ torobinson$ ping google.com ping google.com (4.35.2.172): 56 data bytes 64 bytes 4.35.2.172: icmp_seq=0 ttl=57 time=2.536 ms 64 bytes 4.35.2.172: icmp_seq=1 ttl=57 time=1.447 ms 64 bytes 4.35.2.172: icmp_seq=2 ttl=57 time=1.415 ms ^c --- google.com ping statistics --- 3 packets transmitted, 3 packets received, 0.0% packet loss round-trip min/avg/max/stddev = 1.415/1.799/2.536/0.521 ms tmac:~ torobinson$ python python 2.7.3 (v2.7.3:70274d53c1dd, apr  9 2012, 20:52:43)  [gcc 4.2.1 (apple inc. build 5666) (dot 3)] on darwin type "help", "copyright", "credits" or "license" more information. >>> import urllib2 >>> urllib2.urlopen('http://google.com') traceback (most recent call last):   file "<stdin>", line 1, in <module>   file "/library/frameworks/python.framework/versions/2.7/lib/python2.7/urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout)   file "/library/frameworks/python.framework/versions/2.7/lib/python2.7/urllib2.py", line 400, in open response = self._open(req, data)   file "/library/frameworks/python.framework/versions/2.7/lib/python2.7/urllib2.py", line 418, in _open '_open', req)   file "/library/frameworks/python.framework/versions/2.7/lib/python2.7/urllib2.py", line 378, in _call_chain result = func(*args)   file "/library/frameworks/python.framework/versions/2.7/lib/python2.7/urllib2.py", line 1207, in http_open return self.do_open(httplib.httpconnection, req)   file "/library/frameworks/python.framework/versions/2.7/lib/python2.7/urllib2.py", line 1177, in do_open raise urlerror(err) urllib2.urlerror: <urlopen error [errno 61] connection refused>

what possibly cause this?

edit: abarnert put me on right path. works once install proxyhandler:

    proxy_support = urllib2.proxyhandler({})     opener = urllib2.build_opener(proxy_support)     urllib2.install_opener(opener)     response = urllib2.urlopen("http://google.com")     print response.read()


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