Better way to order call methods inside method -

let's supose following piece of code:

private void createdependencies() {     inject(afake.class,            whatevera());     inject(cfake.class,            whateverc());     inject(bfake.class,            whateverb());     inject(dfake.class,            whateverd());     // ... , 200 more } 

which better way order alphabetically createdependencies->inject(...) methods, have following result?

private void createdependencies() {     inject(afake.class,            whatevera());     inject(bfake.class,            whateverb());     inject(cfake.class,            whateverc());     inject(dfake.class,            whateverd());     // ... , 200 more } 

maybe bash script? maybe creating hole (and boring) java project , using sorting algorithm?

after several time searching easy way this, best/easy way (for me):

• copy content of createdependencies() method file, let's aux.txt.

• save it.

• open vim , run:

  :%s/,\n/, /g

  :%sort

  :x

• now copy content of aux.txt , replace content of createdependencies() in real file.

• run reformat in ide! :)