sql - How to select sub string in oracle? -

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i have scenario data below:

chapter 18 unit 10 sect 16  case 1 : want select  chapter 18 above string. case 2 : want select  unit 10 above string. case 3 : want select  sect 16 above string.

thanks & regards, keerthi

using substr:

declare   l_start number := dbms_utility.get_cpu_time; begin in ( t (   select 'chapter ' || level || ' unit ' || level || ' sect ' || level  d dual connect rownum < 100000 ) select substr(d, 1, instr(d, ' ', 1, 2) - 1) chapter      , substr(d,            instr(d, ' ', 1, 2),            instr(d, ' ', 1, 4) - instr(d, ' ', 1, 2)        ) unit      , substr(d,            instr(d, ' ', 1, 4),            length(d) - instr(d, ' ', 1, 4) + 1        ) sect    t ) loop   null; end loop;  dbms_output.put_line((dbms_utility.get_cpu_time - l_start) || ' hsec'); end;  126 hsec

using regexp:

declare   l_start number := dbms_utility.get_cpu_time; begin in ( t (   select 'chapter ' || level || ' unit ' || level || ' sect ' || level  d dual connect rownum < 100000 ) select regexp_substr(d, 'chapter [0-9]*') chapter      , regexp_substr(d, 'unit [0-9]*') unit      , regexp_substr(d, 'sect [0-9]*') sect    t ) loop   null; end loop;  dbms_output.put_line((dbms_utility.get_cpu_time - l_start) || ' hsec'); end;  190 hsec

so solution regexp slower, more readable, if use regexp.


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