java - Integer.parseInt("9999999990"); -

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• unexpected numberformatexception while parsing hex string int value 5 answers

i getting numberformatexception string 9999999990 not when use 1111111110 when call integer.parseint on string. let me know wrong.

string str="9999999990";   int f = integer.parseint("2147483647");// no exception here         int x =integer.parseint(str);   // exception thrown here  

integer.parseint throw exception when it's parsing can't represented int. first example 10 billion, larger largest possible int, little on 2 billion.

integer.parseint(string) delegates integer.parseint(string, 10), version takes radix, , javadocs state:

an exception of type numberformatexception thrown if of following situations occurs:

• the first argument null or string of length zero.
• the radix either smaller character.min_radix or larger character.max_radix.
• any character of string not digit of specified radix, except first character may minus sign '-' ('\u002d') or plus sign '+' ('\u002b') provided string longer length 1.
• the value represented string not value of type int.

(emphasis mine)

if need parsed, can use long.parselong, handle larger numbers.