Piping to different commands based on exit status in bash -

trying achive like:

command | { [[ ${pipestatus[0] == 0 ]] && cmd_pipe_success || cmd_pipe_failed ; } 

e.g. piping different commands, depending on exit-status.

the above exmaple didn't works, e.g.:

command_ok() { sed 's/^/ok /'; } command_no() { sed 's/^/no /'; }  touch x ls -l x 2>&1 | { [[ ${pipestatus[0]} == 0 ]] && command_ok || command_no ; } rm x ls -l x 2>&1 | { [[ ${pipestatus[0]} == 0 ]] && command_ok || command_no ; } 

both prints ok, in both cases runs command_ok.

is possible achieve run command_no when exit-staus of ls nonzero?

i know, possible achieve like

command_ok() { sed 's/^/ok /'; return 0; } command_no() { sed 's/^/no /'; return 0; }  touch x res=$(ls -l x 2>&1) [[ $? == 0 ]] && command_ok <<<"$res" || command_no <<<"$res"  rm x res=$(ls -l x 2>&1) [[ $? == 0 ]] && command_ok <<<"$res" || command_no <<<"$res" 

but want avoid helper variable, nor temp files. possible?

as mentioned, there's no way without getting temp file involved: pipe needs set before original command finished running. however, doing temp file pretty easy:

tempfile=$(mktemp) if command > $tempfile;   command_ok < $tempfile else   command_no < $tempfile fi rm $tempfile